tdf#84650 Fix X-coordinate of SmMatrixNode's elements
which are aligned to left or right against the column.
Change-Id: Ie2b6944bc0dddb0e1589842472298f787fabf596
Reviewed-on: https://gerrit.libreoffice.org/30929
Tested-by: Jenkins <ci@libreoffice.org>
Reviewed-by: Takeshi Abe <tabe@fixedpoint.jp>
diff --git a/starmath/source/node.cxx b/starmath/source/node.cxx
index dfbc819..3db53a9 100644
--- a/starmath/source/node.cxx
+++ b/starmath/source/node.cxx
@@ -2282,7 +2282,6 @@ void SmMatrixNode::Arrange(OutputDevice &rDev, const SmFormat &rFormat)
// align all baselines in that row if possible
aPos = rNodeRect.AlignTo(aLineRect, RectPos::Right, RectHorAlign::Center, RectVerAlign::Baseline);
aPos.X() += nHorDist;
// get horizontal alignment
const SmNode *pCoNode = pTmpNode->GetLeftMost();
@@ -2292,7 +2291,7 @@ void SmMatrixNode::Arrange(OutputDevice &rDev, const SmFormat &rFormat)
// and horizontal alignment
switch (eHorAlign)
{ case RectHorAlign::Left:
aPos.X() = rNodeRect.GetLeft() + aColLeft[j];
aPos.X() = aColLeft[j];
break;
case RectHorAlign::Center:
aPos.X() = rNodeRect.GetLeft() + aColLeft[j]
@@ -2300,7 +2299,7 @@ void SmMatrixNode::Arrange(OutputDevice &rDev, const SmFormat &rFormat)
- rNodeRect.GetItalicCenterX();
break;
case RectHorAlign::Right:
aPos.X() = rNodeRect.GetLeft() + aColLeft[j]
aPos.X() = aColLeft[j]
+ aColWidth[j] - rNodeRect.GetItalicWidth();
break;
default:
