Round calculation to avoid blurry default icons
Having the paper of 21000 x 29700, and nThumbnailSize of 256, the
ratio is 0.0086195286195286195; aThumbnailSize would be calculated
from 255.99999999999999915 x 181.0101010101010095; truncation will
make the end result 255 x 181, and after drawing the icon on that,
it will be stretched to 256x256 (so there will be 255->256 scale).
Change-Id: Ic7d37206b42e2229b36161c215a36e4b71486802
Reviewed-on: https://gerrit.libreoffice.org/c/core/+/131582
Tested-by: Mike Kaganski <mike.kaganski@collabora.com>
Reviewed-by: Mike Kaganski <mike.kaganski@collabora.com>
diff --git a/sfx2/source/control/recentdocsviewitem.cxx b/sfx2/source/control/recentdocsviewitem.cxx
index 6f046e3..5741f59 100644
--- a/sfx2/source/control/recentdocsviewitem.cxx
+++ b/sfx2/source/control/recentdocsviewitem.cxx
@@ -81,7 +81,7 @@ RecentDocsViewItem::RecentDocsViewItem(sfx2::RecentDocsView &rView, const OUStri
nPaperWidth = aInfo.getWidth();
}
double ratio = double(nThumbnailSize) / double(std::max(nPaperHeight, nPaperWidth));
Size aThumbnailSize(nPaperWidth * ratio, nPaperHeight * ratio);
Size aThumbnailSize(std::round(nPaperWidth * ratio), std::round(nPaperHeight * ratio));
if (aExtSize.Width() > aThumbnailSize.Width() || aExtSize.Height() > aThumbnailSize.Height())
{
